yet another subnetting question?

Yet another subnetting question?

XYZ Company is allocated a network IP address of:

192.68.40.0/27 (Class C)

Determine subnet mask using this method:

The Binary: 11111111 . 11111111 . 11111111 . 11100000

255.255.255.224 (Last Octet = 128 + 64 + 32 = 224)

Magic Number is: 32 (Magic Number = Last 1 is in “32’s” place)

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This is where things get fuzzy for me!

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- Question #1: Since this is a Class “C” address, does that dictate that my magic number will be applied in the fourth octet?

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- Question #2: Can you tell me if I am applying the following correctly:

- Network Address: 192.68.40.0/27 (a lost subnet?)

- Subnet 1: 192.68.40.32/27 (32 = subnet, 33-62 = host range, 63 = broadcast)
- Subnet 2: 192.68.40.64/27 (64 = subnet, 65-94 = host range, 95 = broadcast)
- Subnet 3: 192.68.40.96/27 (96 = subnet, 97-126 = host range, 127 = broadcast)
- Subnet 4: 192.68.40.128/27 (128 = subnet, 129-158 = host range, 159 = broadcast)
- Subnet 5: 192.68.40.160/27 (160 = subnet, 161-190 = host range, 191 = broadcast)
- Subnet 6: 192.68.40.192/27 (192 = subnet, 193-222 = host, 223 = broadcast)

- Network Broadcast Subnet: 192.68.40.224/27 (a lost subnet?)

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- Question #3: If the subnets of 192.68.40.0/27 and 192.68.40.224/27 can not be used, what happens with them?